a.[tex]\sqrt{225}[/tex] + [tex]5^{2}[/tex] =...
b.[tex]10^{2}[/tex] - [tex]\sqrt{400}[/tex] =...
Jawaban:
√225 + 5² = 15 + 25 = 40
10² - √400 = 100 - 20 = 80
Jwbn :
[tex]\tt \sqrt{225} + {5}^{2} = [/tex]
[tex]\tt = \sqrt[2]{ {15}^{2} } + (5 \times 5)[/tex]
[tex]\tt = {15}^{ \frac{2}{2} } + (5 + 5 + 5 + 5 + 5)[/tex]
[tex]\tt = {15}^{1} + (10 + 5 + 5 + 5)[/tex]
[tex]\tt = 15 + (15 + 5 + 5)[/tex]
[tex]\tt = 15 + (20 + 5)[/tex]
[tex]\tt = 15 + 25[/tex]
[tex]\tt = 40[/tex]
__
[tex]\tt {10}^{2} - \sqrt{400} = [/tex]
[tex]\tt = (10 \times 10) - \sqrt[2]{ {20}^{2} } [/tex]
[tex]\tt = (10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10) - {20}^{ \frac{2}{2} } [/tex]
[tex]\tt = (20 + 20 + 20 + 20 + 20) - {20}^{1} [/tex]
[tex]\tt = (40 + 40 + 20) - 20[/tex]
[tex]\tt = (80 + 20) - 20[/tex]
[tex]\tt = 100 - 20[/tex]
[tex]\tt = 80[/tex]
<(°5Π―iiz°)>